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MT > Exemplos MT Weibull++
MT A seguir apresentamos quatro exemplos onde foi utilizado o Weibull++ MT para analisar os dados provenientes dos histórico de manutenção de máquinas (equipment downtime log data). Será ilustrado o Weibull++ MT realizando a conversão dos dados e a análise automática. [Exemplo 1] [Exemplo 2] [Exemplo 3] [Exemplo 4] |
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Consider a very simple system comprising only two components, A and B. The system runs from 8 a.m. to 5 p.m. Monday through Friday. When a failure is observed, the system undergoes repair and the failed component is replaced. The date and time of each failure is recorded in an equipment downtime log, along with an indication of the component that caused the failure. The date and time when the system was restored is also recorded. The downtime log for this simple system is given next. |
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Note that: For this example, we will assume that an engineer began recording these events on January 1, 1997 at 12 p.m. and stopped recording on March 18, 1997 at 1 p.m., at which time the analysis was
performed. Information for events prior to January 1 are unknown. Analysis
Objective & Discussion The objective of the analysis is to obtain failure and
repair distributions for each component. To do this, times-to-failure and
times-to-repair for each component need to be computed from the data in
the above table. Once the times-to-failure and times-to-repair data are
obtained, a life distribution will be fitted to each data set. The
principles and theory for fitting a life distribution is presented are detail
in ReliaSoft's
on-line life data analysis reference. Solution
to Example 1 Obtaining Failure and Repair Times for Component A We begin the analysis by looking at component A. The first
time that component A is known to have failed is recorded in row 1; thus,
the first age (or time-to-failure) for A is the difference between the
time we began recording the data and the time when this failure event happened.
Since the system operates in shifts, the component is not aging when the
system is down due to the failure of another component. Therefore, this
time must be taken into account. 1. The First Time-To-Failure for Component A, TTFA[1]
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Thus, TTFA[1]=5+8=13 hours. 2. The First Time-To-Repair for Component A, TTRA[1] TTRA[1] = (Jan 02 1997 / 7:49 PM - Jan 02 1997 / 4:00 PM) = 3:49 =3.8166 hrs (Note that in the case of repair actions, shifts are not taken into account since it is assumed that repair actions will be performed as needed to bring the system up.) 3.
The Second Time-To-Failure for Component A, TTFA[2] This is shown graphically next using green to show the operating times of A and orange to show the downtimes of the system for reasons other than the failure of A (and to the closest hour). |
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To illustrate this mathematically, we will utilize a function t, which, given a range of times, returns the shift hours worked during that period. In other words, for this example t(1/1/97 3:00 a.m. - 1/1/97 6:00 p.m.) = 9 hrs given an 8 a.m. to 5 p.m. shift. Furthermore, we will show the date and time a failure occurred as DTO and the date and time a repair was completed at DTR with a numerical subscript indicating the row that this entry is in (e.g. DTO4 for the date and time a failure occurred in row 4).Then, the total possible hours (TPH) that component A could have operated from the time it was repaired to the time it failed the second time is: TPH= t (DTO4 – DTR1),TPH=t (DTO4 – DTR1)=9 Days*9 hours + 7:26 hrs=88:26 hrs The time that component A was not operating (NOP), during normal hours of operation, is the time that the system was down due to failure of component B, or: NOP= t (DTO2
– DTR2)+ t ( DTO3 – DTR3) Thus, the second time-to-failure for component A, TTFA[2], is: TTFA[2]= TPH- NOP 4.
The Second Time-To-Repair for Component A, TTRA[2] TTRA[2] t (DTO4 – DTR4) = (3 h, 49 m)=3.8166 hrs 5. Computing the Rest TTFA[3]=8.9333 and TTRA[3]= 0.4166 6.
Creating the Data Sets
Since our analysis time ends on March 18, 1997 at 1:00 pm and component A has operated successfully from the last time it was replaced or March 13, 1997 at 5:13 p.m., the additional time of successful operation is: TPH= t
(End Time – DTR19)=
(4 days*9 hrs/day + 5:00 hrs)=41:00 hrs Thus, the remaining time that component A operated without failure is: TTS=TPH-NOP=33:36=33.6 hrs. 7.
Data for Life Data Analysis in
Weibull++ |
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8. Automated Analysis in Weibull++ MT Use the Set Shift Pattern window to specify 8:00 a.m. to 5:00 p.m. shifts seven days a week, as shown in Figure 2. The utility will automatically convert the equipment downtime log data to time-to-failure and time-to-repair data and fit failure and repair distributions to the data set. The results are displayed in the Weibull++ MT Results sheet, as shown in Figure 3. 9.
Discussion Obviously, when dealing with a large system composed of multiple levels (e.g. subsystems, sub-subsystems, assemblies and parts), this analysis process can be very cumbersome. Before the release of Weibull++ MT, it took a ReliaSoft engineer over 40 hours to reduce an equipment downtime log to usable data for analysis in Weibull++. The same analysis was later performed in Weibull++ MT in seconds. [Exemplo 1] [Exemplo 2] [Exemplo 3] [Exemplo 4] O Weibull++ MT é uma versão especial do Weibull++ 6 para as aplicações de manutenção e processo. Veja a Home page do Weibull++ 6 para mais detalhes sobre as características e funcionalidades disponíveis neste software de análise de dados de vida. |
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